perf: O(N*M) -> O(N log N) combat initiative loop (#3106)#3107
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Двойной цикл initiative(max..min) × combat_list заменён на std::list::sort по инициативе + один проход по списку. Было: до 201 прохода по combat_list (инициативы от -100 до 100). Стало: одна сортировка O(N log N) + один проход O(N). Round check занимал 95% времени perform_violence (130-189ms). Co-Authored-By: Claude Opus 4.6 (1M context) <noreply@anthropic.com>
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Summary
Round checkвperform_violenceзанимал 95% времени (130-189ms при пульсе 40ms).Причина: двойной цикл
for (initiative = max..min)×for (combat_list)= O(N×M), где M = до 201 (диапазон инициатив -100..100).Фикс:
combat_list.sort()по убыванию инициативы + один проход = O(N log N + N).Test plan
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