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Maximum_Product_Subarray.cpp
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178 lines (168 loc) · 4.08 KB
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// Source : https://oj.leetcode.com/problems/maximum-product-subarray/
// Author : zheng yi xiong
// Date : 2014-11-5
/**********************************************************************************
*
* Find the contiguous subarray within an array (containing at least one number) which has the largest product.
* For example, given the array [2,3,-2,4],
* the contiguous subarray [2,3] has the largest product = 6.
*
**********************************************************************************/
class Solution {
public:
int maxProduct(int A[], int n) {
int positiveProductFirst = 0, positiveProductLast = 0, midProduct = 1;
//positiveProductFirst: positive product before first negative number
//positiveProductLast: positive product after last negative number
//midProduct: the product except positiveProductFirst positiveProductLast and negativeFirst negativeLast
int negativeFirst = 0, negativeLast = 0; //first negative number and last one
int max_product = 0x80000000; //min int
int i = 0;
while( (i < n) && (0 == A[i])) ++i;
if (i >= n)
{
return 0;
}
for (; i < n; ++i)
{
if (0 == A[i])
{
if (0 == negativeLast)
{
if (0 != negativeFirst)
{
if (positiveProductLast > positiveProductFirst)
{
positiveProductFirst = positiveProductLast;
}
else if (0 == positiveProductFirst)
{
positiveProductFirst = negativeFirst;
}
}
}
else
{
positiveProductFirst = (0 == positiveProductFirst) ? 1 : positiveProductFirst;
positiveProductLast = (0 == positiveProductLast) ? 1 : positiveProductLast;
if (0 < midProduct)
{
positiveProductFirst *= midProduct * negativeFirst * negativeLast * positiveProductLast;
}
else
{
if ( (positiveProductFirst * negativeFirst) < (negativeLast * positiveProductLast) )
{
positiveProductFirst *= negativeFirst * midProduct;
}
else
{
positiveProductFirst = positiveProductLast * negativeLast * midProduct;
}
}
}
if (max_product < positiveProductFirst)
{
max_product = positiveProductFirst;
}
positiveProductFirst = 0;
positiveProductLast = 0;
negativeFirst = 0;
negativeLast = 0;
midProduct = 1;
if (0 > max_product)
{
max_product = 0;
}
while( (i + 1 < n) && (0 == A[i + 1])) ++i;
}
else if (0 > A[i])
{
if (0 == negativeFirst)
{
negativeFirst = A[i];
}
else
{
if (0 != positiveProductLast)
{
midProduct *= positiveProductLast;
}
if (0 != negativeLast)
{
midProduct *= negativeLast;
}
positiveProductLast = 0;
negativeLast = A[i];
}
}
else
{
if (0 == negativeFirst)
{
if (0 == positiveProductFirst)
{
positiveProductFirst = A[i];
}
else
{
positiveProductFirst *= A[i];
}
}
else
{
if (0 == positiveProductLast)
{
positiveProductLast = A[i];
}
else
{
positiveProductLast *= A[i];
}
}
}
}
if (0 != A[n-1])
{
if (0 == negativeLast)
{
if (0 != negativeFirst)
{
if (positiveProductLast > positiveProductFirst)
{
positiveProductFirst = positiveProductLast;
}
else if (0 == positiveProductFirst)
{
positiveProductFirst = negativeFirst;
}
}
}
else
{
positiveProductFirst = (0 == positiveProductFirst) ? 1 : positiveProductFirst;
positiveProductLast = (0 == positiveProductLast) ? 1 : positiveProductLast;
if (0 < midProduct)
{
positiveProductFirst *= midProduct * negativeFirst * negativeLast * positiveProductLast;
}
else
{
if ( (positiveProductFirst * negativeFirst) < (negativeLast * positiveProductLast) )
{
positiveProductFirst *= negativeFirst * midProduct;
}
else
{
positiveProductFirst = positiveProductLast * negativeLast * midProduct;
}
}
}
if (max_product < positiveProductFirst)
{
max_product = positiveProductFirst;
}
}
return max_product;
}
};