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leetcode40.cpp
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88 lines (83 loc) · 2.36 KB
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/*************************************************
Author: wenhaofang
Date: 2021-07-07
Description: leetcode40 - Combination Sum II
*************************************************/
#include <iostream>
#include <vector>
#include <string>
#include <unordered_map>
#include <unordered_set>
#include <stack>
#include <queue>
#include <algorithm>
#include <math.h>
using std::vector;
using std::string;
using std::unordered_map;
using std::unordered_set;
using std::stack;
using std::queue;
using std::priority_queue;
using std::max;
using std::min;
using std::pair;
using std::cin;
using std::cout;
using std::endl;
/**
* 方法一:回溯
*
* 实际时间复杂度:Runtime: 0 ms, faster than 100.00% of C++ online submissions
* 实际空间复杂度:Memory Usage: 10.4 MB, less than 94.21% of C++ online submissions
*/
class Solution {
public:
vector<vector<int>> combinationSum2(vector<int>& candidates, int target) {
vector<vector<int>> ans;
vector<int> cur;
sort(candidates.begin(), candidates.end());
backtrack(ans, cur, candidates, 0, target);
return ans;
}
void backtrack(
vector<vector<int>>& ans,
vector<int>& cur,
vector<int>& candidates,
int begin,
int resNum
) {
if (resNum == 0) {
ans.push_back(cur);
return;
}
int n = candidates.size();
for (int i = begin; i < n; i++) {
int num = candidates[i];
if (i > begin && num == candidates[i - 1]) {
continue;
}
if (num > resNum) {
break;
}
cur.push_back(num);
backtrack(ans, cur, candidates, i + 1, resNum - num);
cur.pop_back();
}
}
};
/**
* 测试
*/
int main() {
Solution* solution = new Solution();
vector<int> candidates = {10, 1, 2, 7, 6, 1, 5};
int target = 8;
vector<vector<int>> ans = solution -> combinationSum2(candidates, target);
for (vector<vector<int>>::iterator outer_iter = ans.begin(); outer_iter != ans.end(); outer_iter++) {
for (vector<int>::iterator inner_iter = (*outer_iter).begin(); inner_iter != (*outer_iter).end(); inner_iter++) {
cout << (*inner_iter) << " ";
}
cout << "\n";
}
}