To my understanding the numpy dtype <M8[ns] is the byte-order equivalent to datetime64[ns] on little-endian hardware, whereas on big-endian machines datetime64[ns] == >M8[ns].
So we are enforcing little-endianess of our dataframes in tivs_from_timeseries()?
class STAREDataFrame(geopandas.GeoDataFrame):
make_tids():
if not pandas.api.types.is_datetime64_any_dtype(start_col.dtype): <= Allowing any datetime64 object
raise TypeError('dtype of column must be numpy.datetime64')
# which calls
temporal_conversions.tivs_from_timeseries():
if not series.dtype == '<M8[ns]': <= enforcing little-endianess?
Not that I can even think of a big-endian machine nowadays, but perhaps we should add a note (or issue a warning) to this?
import sys
sys_is_le = sys.byteorder == 'little'
I say this because by default panadas and datetime make datetime64[ns] objects which defaults to that machine's byte-order.
Also, am I correct that STATEPandas does not want/support datatimes with timezone (UTC) encoding (i.e., not '<M8[ns, UTC]', 'datetime64[ns UTC]')?
To my understanding the numpy dtype
<M8[ns]is the byte-order equivalent todatetime64[ns]on little-endian hardware, whereas on big-endian machinesdatetime64[ns] == >M8[ns].So we are enforcing little-endianess of our dataframes in
tivs_from_timeseries()?Not that I can even think of a big-endian machine nowadays, but perhaps we should add a note (or issue a warning) to this?
I say this because by default panadas and datetime make
datetime64[ns]objects which defaults to that machine's byte-order.Also, am I correct that STATEPandas does not want/support datatimes with timezone (UTC) encoding (i.e., not '<M8[ns, UTC]', 'datetime64[ns UTC]')?